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-0.1x^2+2.4x-1.9=0
a = -0.1; b = 2.4; c = -1.9;
Δ = b2-4ac
Δ = 2.42-4·(-0.1)·(-1.9)
Δ = 5
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(2.4)-\sqrt{5}}{2*-0.1}=\frac{-2.4-\sqrt{5}}{-0.2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(2.4)+\sqrt{5}}{2*-0.1}=\frac{-2.4+\sqrt{5}}{-0.2} $
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